Opto-Coupler

1. AC Interface

Using HCPL-3700 from Agilent Technology.

For the mode of Input Clamp Voltage, we have

Vihc2 = 6.7 v

|Iin| = 10 mA

we have

Vr = Vpk - Vihc2 = 240*1.414 - 6.7 = 332.7 v

So

Rx = Vr / |Iin| = 332.7 / 10 = 33.3 K

Rx/2 = 16.7 K

Use Rx/2 = 18.7 K, 1%, so

Px/2 = (Vr/2)2 / Rx/2 = 1.5w

Choose

Rx/2 = 18.7 K,1%, 1.5 w

Question:

Div2 is a flip-flop to divide 120 Hz for 60 Hz

RL is not required ???

2. Isolation Amplifier

Using HCNR-0201 from Agilent Technology.

Data sheet gives IF = 1 ~ 20 mA, choose IF = 2 mA, we have

R3 = (VCC - VF)/IF = 5/2 = 2.5 K

Data sheet gives

IPD1 = K1 * IF = 0.5 * 2 = 1 mA

so

R1 = VIN / IPD1 = 5/1 = 5 K

as VIN is an analog signal out of a 5-v DAC (Digital Analog Converter)

Data sheet gives

IPD2 = K3 * IPD1 = 1 * 1 = 1 mA

so

R2 = VCC / IPD2 = 5/1 = 5 K

 

C1 is for C1R1 to meet Fmax

C2 is for C2R2 to meet Fmax